A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft

Answer:a= 200b = 210Step-by-step explanation:My assumption is, we have to find the length of sides of rectangleGivenperimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)area = a*b = 42,000 ft^2 (ii)from eq (1)2a + 2b = 820=> 2(a+b) = 820=> a+b = 820/2=> a + b = 410=> a = 410-b   (iii)putting the value of a in eq(ii), we get(410-b) *b = 42,000410b - b^2 = 42,0000 = b^2 - 410b + 42000b^2 - 410b + 42000 = 0 b^2- 200b- 210b + 42000 = 0b(b-200)-210(b-200) = 0(b-200)(b-210) = 0or b= 210 and b = 200if b is larger side than b =210By putting value of b in eq(iii),a = 410 -210 = 200